Fix typo
Change-Id: I8e90b4592d041e63bd2efa914446db96dd293ac9 Reviewed-on: https://gerrit.libreoffice.org/63964 Reviewed-by: Julien Nabet <serval2412@yahoo.fr> Tested-by: Julien Nabet <serval2412@yahoo.fr>
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Julien Nabet
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@@ -588,7 +588,7 @@ namespace basegfx
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{
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// This is the central subdivider. The strategy is to use the first two entries
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// from the traversing edges as a potential trapezoid and do the needed corrections
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// and adaptions on the way.
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// and adaptations on the way.
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// There always must be two edges with the same YStart value: When adding the polygons
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// in the constructor, there is always a topmost point from which two edges start; when
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@@ -661,7 +661,7 @@ namespace basegfx
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B2DPoint aLeftEnd(aLeft.getEnd());
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B2DPoint aRightEnd(aRight.getEnd());
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// check if end points are on the same line. If yes, no adaption
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// check if end points are on the same line. If yes, no adaptation
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// needs to be prepared. Also remember which one actually is longer.
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const bool bEndOnSameLine(fTools::equal(aLeftEnd.getY(), aRightEnd.getY()));
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bool bLeftIsLonger(false);
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